Answer:
Explanation:
It looks like you need to solve this system of equations.
That means we need to find a value for x and a value for y that makes both equations true.
Since both equations have a 3y in them, this system is ready to use a method called "elimination method"
Since the x terms are lined up, and the y terms are lined up, the equal signs are lined up, and the constants are lined up...you can subtract the bottom equation from the top equation.
5x + 3y = 41
2x + 3y = 20
Subtract and you will get
3x + 0y =21
We don't need to write that 0y, because it is 0.
3x = 21, now divide by 3
x = 7, almost finished!
Use x = 7 in either of the original equations to find y.
5x + 3y = 41 and x = 7
5•7+ 3y = 41
35 + 3y = 41
-35 -35
3y =6
y = 2
So the solution is x=7 and y=2
That can also be written as an ordered pair (7, 2)