Question

A ball is thrown 24 m/s into the air. How high does it go?556.4 m0 m29.4 m-556.4 m

Answer 1

the initial speed of the ball is u = 24 m/s

the acceleration is a = 9.8 m/s^2

also the ball will have zero velocity at the top,

so final velocity is v = 0

so the distance(s) covered by the ball is ,

`\begin{gathered} v^2=u^2-2gs \\ 0=24^2-2*9.8* s \end{gathered}`

`\begin{gathered} 19.6s=576 \\ s=(576)/(19.6)=29.4 \end{gathered}`

so the ball was 29.4 m high.