b) In general, a sine function is differentiable (smooth). The given function is not differentiable at each one of its peaks; therefore, it cannot be expressed using sinusoidal functions.
It is not a sinusoidal function.
e) Notice that V(0)=V(8); in other words, the triangular shape of the function repeats itself every 8μs.
Thus, the period of the function is 8 micro-seconds.
The voltage starts at 0kV, increases at a constant rate up to its maximum, and then decreases immediately to 0kV
f) Notice that, according to the graph, the peak of the function is at 20kV.
We will suppose that the 'axis' of the curve refers to its midline, due to the lack of specificity.
The equation of the midline is y=(maximum+minimum)/2. Therefore, in our case,
The axis of the curve is V(x)=10.
g) The values of V go from 0 to 20kV.
Thus, the range of the function is [0,20], where the units are in kV.
h) As stated in part e), a cycle of the function takes 8 seconds to complete; hence, 15 cycles is equivalent to
Then, the domain of the function is [0,120], where the units are in micro-seconds