Question

What is the factored form of n3+512 (pleas help fast)

A- (n-8)(n^2+8n+64)
B- (n+4)(n^2-4n+128)
C- (n-4)(n^2+4n+128)
D- (n+8)(n^2-8n+64)

Answer 1

Since both terms are perfect cubes, factor using the sum of cubes formula,

a³+b³=(a+b)(a²-ab+b²) where

a=n and b=8

(n+8)(n²-8n+64)

Answer

(n+8)(n²-8n+64)

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Carryonlearing

Answer 2

Explanation:

The only one that has a chance of being correct is D. That's because the first term is correct and you have to assume that the second one is as well.

cubrt(512) = 8

The first term is (n + 8)

The second term is (n^2 - 8*n + 8^2) = n^2 - 8n + 64

All the other answers have the wrong first term

A: it should be n + 8 not n - 8

B and C are both wrong because the cube root of 512 is 8 not 4.