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If the length of a rectangle is expressed by2x2 + 4x – 8 and the width is 3x. What is the area ofthe rectangle ?

If the length of a rectangle is expressed by2x2 + 4x – 8 and the width is 3x. What is the area ofthe rectangle ?
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If the length of a rectangle is expressed by2x2 + 4x – 8 and the width is 3x. What is the area ofthe rectangle ?

User Alex Smith
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\begin{gathered} L=2x^2+4x-8 \\ w=3x \\ \text{Area}=L* w \\ \text{Area}=(2x^2+4x-8)*3x \\ \text{Area}=6x^3+12x^2-24x \end{gathered}

User Zloster
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