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First drop down answer choices A. pi/4 B. pi/ 2 C. 4pi D. piSecond drop down answer choices A. pi/4 B. pi/ 2 C. 4pi D. piThird drop down answer choices A. Larger B. Smaller Forth drop down answer choices A. Larger B. Smaller

First drop down answer choices A. pi/4 B. pi/ 2 C. 4pi D. piSecond drop down answer-example-1
User Tom Walker
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1 Answer

1 vote

Let 'a' represent the ratio of the arc length to its radius.

Given for the first circle,


\begin{gathered} \text{Arc length=4pi} \\ \text{Radius}=16\text{units} \end{gathered}

Therefore,


\begin{gathered} a_1=(4\pi)/(16)=(\pi)/(4) \\ \therefore a_1=(\pi)/(4) \end{gathered}

Given for the second circle,


\begin{gathered} \text{Arc length=}5\pi \\ \text{Radius}=5units \end{gathered}

Therefore,


\begin{gathered} a_2=(5\pi)/(5)=\pi \\ \therefore a_2=\pi \end{gathered}

Hence,


\begin{gathered} \pi>(\pi)/(4) \\ \therefore a_2>a_1 \end{gathered}

Final answers

First drop down


(\pi)/(4)\text{ (OPTION }A)

Second drop down


\pi\text{ (OPTION D)}

Third drop down


Larger\text{ (OPTION A)}

Fourth drop down


Larger\text{ (OPTION A)}

User Akash Shrivastava
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