Given:
The original plan for a stage x feet long and x feet wide had to be made smaller to fit the space.
The stage needs to be 6 feet narrower and 4 feet shorter than her original plan.
To find:
The area
Step-by-step explanation:
According to the problem,
The length of the smaller stage becomes,

The width of the smaller stage becomes,

So, the area becomes,

Final answer:
The correct option is A.

The area of the smaller stage is,
