Question

Please help due in 20 minutes

Answer 1

• <PTQ=90

In ∆PTQ

Apply Pythagorean theorem

`\\ \tt\hookrightarrow PT^2=PQ^2+QT^2`

`\\ \tt\hookrightarrow PT^2=15.4^2+9.3^2=323.16`

`\\ \tt\hookrightarrow PT=17.9`

In ∆TRQ

`\\ \tt\hookrightarrow tan44.4=(QT)/(TR)=(9.3)/(TR)`

`\\ \tt\hookrightarrow 0.9=(9.3)/(TR)`

`\\ \tt\hookrightarrow TR=(9.3)/(0.9)=10.3`

• PR=PT+TR=10.3+17.9=28.2cm

Now

Area:-

`\\ \tt\hookrightarrow 1/2bh`

`\\ \tt\hookrightarrow 1/2(28.2)(9.3)`

`\\ \tt\hookrightarrow 14.1(9.3)`

`\\ \tt\hookrightarrow 131.13cm^2`