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A line passes through the point (-4,-8) and has a slope of 5/2Write an equation in point-slope form for this line.

User Pjj
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The point-slope formula of a line can be expressed by the following equation:


y-y_1=m\cdot(x-x_1)

Where m is the slope and (y1, x1) is a point that belong to the line. For this problem we were given a line with slope 5/2 and a point (-4,-8). By replacing these values on the general expression above we have:


\begin{gathered} y-(-8)=(5)/(2)\cdot(x-(-4)) \\ y+8=(5)/(2)\cdot(x+4) \end{gathered}

User Arfeo
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