139k views
2 votes
The red is the answer I just need the steps that lead to the answer

The red is the answer I just need the steps that lead to the answer-example-1

1 Answer

1 vote

The trapezoids LMNK and LMAB are simillar, which means that their sides are related by the same ratio. With this we can form the following equation:


(2x-2)/(-15+6x)=(-15+6x)/(32)

We need to solve for x.


\begin{gathered} 32\cdot(2x-2)=(-15+6x)^2 \\ 64x-64=225-180x+36x^2 \\ 36x^2-180x-64x+225+64=0 \\ 36x^2-180x-64x+225+64=0 \\ 36x^2-244x+289=0 \end{gathered}

Now we have to find the roots of the quadratic equation.


\begin{gathered} x=\frac{-(-244)\pm\sqrt[]{(-244)^2-4(36)(289)}}{2\cdot36} \\ x=\frac{244\pm\sqrt[]{17920}}{64} \\ x=(244\pm133.87)/(64) \\ x=(244+133.87)/(64)=5.9 \\ x=(244-133.87)/(64)=1.72 \end{gathered}

Therefore the midsegment is equal to:


\begin{gathered} -15+6\cdot(5.9)=20.4_{} \\ or \\ -15+6\cdot(1.72)=-4.68 \end{gathered}

Since the length can't be negative, the correct result is 20.4.

User Vladimir Balandin
by
6.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.