Question

B1= 5 1/6 yd, b2 = 3 1/3 yd, h= 8 yd

Answer 1

We can calculate the area of the trapezoid by using the formula below:

`\text{Area of trapezoid=}(b_1+b_2)/(2)\text{.h}`

where b1 and b2 are the base and h is the height

From the question, b1=5 1/6 = 31/6

b2= 3 1/3 = 10/3

h=8

substitute the values into the formula and evaluate

`\text{Area of trapezoid=}((31)/(6)+(10)/(3))/(2).8`
`=((31+20)/(6))/(2)*8`

`=((51)/(6))/(2)*8`
`=(51)/(6)*4`
`=(51)/(3)*2`
`=17*2`
`=34yd^2`