Answer:
To cause destructive interference at point O, the upper speaker must be raised by a minimum vertical distance of 1.66m
Explanations:
The distance between the upper and lower speakers before destructive interference is h
Since the height between the two speakers, h = 2.82 m
h/2 = 2.82/2 = 1.41 m
Using the Pythagora's theorem
![\begin{gathered} r^2_1=8^2+1.41^2 \\ r^2_1\text{ = 64 + }1.9881 \\ r^2_1\text{ = }65.9881 \\ r_1\text{ = }\sqrt[]{65.9881} \\ r_1\text{ = }8.12\text{ m} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/nwg81b6b09phgrxb18hr0e58wzjfk31eko.png)
Since r₁ = r₂
r₂ = 8.12 m
To cause a destructive interference, let us move the speaker on the top by a distance x
We can redraw the diagram as shown below:
The new distance from the midpoint = x + 1.41
The speed of sound in air, v = 343 m/s
The frequency of sound, f = 380 Hz
To calculate the wavelength of the sound produced by the speakers, use the equation:
v = λf
343 = λ x 380
λ = 343/380
λ = 0.903 m
Note that the value of r₁ now will change because the upper speaker has been shifted by a distance x. The value of r₂ remains 8.12m because the speaker at the bottom is not shifted
To find the new value of r₂ use the equation:
r₁ - r₂ = λ / 2
r₁ - 8.12 = 0.903/2
r₁ - 8.12 = 0.45
r₁ = 0.45 + 8.12
r₁ = 8.57 m
To know the value of x, use Pythagora's theorem for the second diagram above
![\begin{gathered} r^2_1=8^2+(x+1.41)^2 \\ 8.57^2=8^2\text{ }+(x+1.41)^2 \\ 73.44\text{ - 64 = }(x+1.41)^2 \\ (x+1.41)^2\text{ = }9.44 \\ x\text{ + 1.41 = }\sqrt[]{9.44} \\ x\text{ + 1.41 = }3.07 \\ x\text{ = 3.07 - 1.41} \\ x\text{ = }1.66\text{ m} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/d2z98poj0sjh0o09ubm9elo9nir7n5o79e.png)
To cause destructive interference at point O, the upper speaker must be raised by a minimum vertical distance of 1.66m