So we have to find how much time those 4 appointments will take. Since the duration of each appointment is given in fractions it's important to remember a properties of fractions:

It is also important to remember the relation between the mix number notation and the usual fraction number notation:

With all of this in mind we can start working on the question. The four appointments consist of two 3/4 hr new patient visits, one 1 1/4 hr serious injury visit and one 3/4 hr dental sealing. The time it will take Roy to finish all of them (t) is equal to the sum of their individual times:

Using what we saw about mix number notation and fractions we get:

Then we have:

So the answer is 7/2 hours.