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How many grams of chlorine will be needed to make 75.0 grams of C2H2Cl4?2Cl2+C2H2=C2H2Cl4(Performed at STP)

User Arieltools
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1 Answer

6 votes

Step-by-step explanation:

The question gives us:

C2H2 + 2Cl2 → C2H2Cl4

First, let's transform 75 grams of C2H2Cl4 into moles. We need to use the following formula:

n = m/MM

MM of C2H2Cl4 = 167.848 g/mol

n = 75/167.848

n = 0.4468 moles

The ratio between Cl2 and C2H2Cl4 is 2:1.

2 moles of Cl2 ---- 1 mole of C2H2Cl4

x moles of Cl2 ---- 0.4468 moles of C2H2Cl4

x = 0.89 moles

Now let's transform 0.89 moles of Cl2 into grams:

m = n*MM

MM of Cl2 = 70.9 g/mol

m = 0.89*70.9 = 63.4 g

Answer: 63.4 g

User Inerte
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