We need to find the area of a sector of circle, bounded by a 114° arc. That sector is a fraction of the circumference, let's calculate it:
We have an arc of 114°, while the complete circumference has 360°.
The fraction of circle from we are going to calculate the area is:
![(114)/(360)](https://img.qammunity.org/2023/formulas/mathematics/college/h2cui2b3n5tzicyf0crul1qin4kpf0anhb.png)
Now, we can estimate the total area of the circle of radius 6, and then multiply it by the fraction of circumference that concerns us: 114/360.
The area of the cicle is:
![\pi\cdot r^2=\pi\cdot(6m)^2=36\pi m^2](https://img.qammunity.org/2023/formulas/mathematics/college/yusiytzztvq28xjhqmbickvrx2qbuty08m.png)
Now, the area of the sector is:
![A=(114)/(360)\cdot36\pi m^2](https://img.qammunity.org/2023/formulas/mathematics/college/am9ncuq5rfniz85g08p4teh7ukcps3ktik.png)
360 is ten times 36, so:
![A=(114)/(10)\pi m^2](https://img.qammunity.org/2023/formulas/mathematics/college/mnggu3wyv667wwi6jhp3p6e4dfqgucirly.png)
Now simplifying, the half of 114 is 57, while the half of 10 is 5, then:
![A=(57)/(5)\pi m^2](https://img.qammunity.org/2023/formulas/mathematics/college/jk8xlt3ijn0rqok86qqu7n6mfj7i2umu6w.png)