Question

In a class of students, the following data table summarizes how many students have acat or a dog. What is the probability that a student has a dog given that they have acat?Has a cat Does not have a catHas a dog615Does not have a dog27

Answer 1

The probability is determined by

`\begin{gathered} P(\text{has a dog given has a cat})=\frac{\text{Number of people who has a dog and who has a cat}}{\text{Number of people of who has a cat}} \\ P(\text{has a dog given has a cat})=(6)/(6+2) \\ P(\text{has a dog given has a cat})=(6)/(8) \\ P(\text{has a dog given has a cat})=(3)/(4) \end{gathered}`

Therefore, the probability that a student has dog given that they have a cat is 3/4 or 0.75