Question

Use the balanced equation to solve the problem.2Na+ Cl₂ → 2NaCl6.00mol Na and 1.36mol Cl₂ are placed in a container. They react to form NaCl.What is the limiting reactant?Cl₂How many moles NaCl are made?I mol NaCl

Answer 1

In this question, we have to find the limiting reactant and also how many moles of product will be made, the reaction is the following:

2 Na + Cl2 -> 2 NaCl

The molar ratios are:

2 Na = 1 Cl2

2 Na = 2 NaCl

1 Cl2 = 2 NaCl

We have:

6.00 moles of Na

1.36 moles of Cl2

According to the molar ratio, if we have 1.36 moles of Cl2, we would need:

2 Na = 1 Cl2

x Na = 1.36 Cl2

x = 2.72 moles of Na

This means that Cl2 is the limiting reactant

Using the limiting reactant, we can find how many moles of the product will be made, using again the molar ratio between them

1 Cl2 = 2 NaCl

1.36 Cl2 = x NaCl

x = 2.72 moles of NaCl

Answers:

Cl2 is the limiting reactant

2.72 moles of NaCl