Question

Is 30.8 g of chloroform with 32.4 g of heptane and 63.8 g Of acetyl bromide. Calculate the percent by mass of each component of the solution. Be sure each of your answer injuries has the correct number of significant digits. Component:Chloroform mass %?Heptane mass %?Acetyl bromide%?

Answer 1

First,

we have 3 compounds in the solution:

-Chloroform

-Heptane

-Acetyl bromide

Mass % = (Mass solute / Mass of solution) x 100

Mass of solution = 30.8 g of Chloroform + 32.4 g of Heptane + 63.8 g of Acetyl bromide = 127 g

------------------------------------------------------------------------

- Mass % Chloroform = (30.8 g / 127 g ) x 100 = 24.2 % (w/w)

- Mass % Heptane = (32.4 g / 127 g) x 100 = 25.5 % (w/w)

- Mass % Acetyl bromide = (63.8 g / 127 g) = 50.2 % (w/w)