Question

Hello,Can you please help me with question# 5 in the picture? thank you

Answer 1

`a_1=9,for\text{ }n\ge2`
`\begin{gathered} a_1=9 \\ a_2=(2)/(3a_(2-1)) \\ a_2=(2)/(3a_1) \\ a_2=(2)/(3(9)) \\ a_2=(2)/(27) \end{gathered}`
`\begin{gathered} a_3=(2)/(3a_(3-1)) \\ a_3=(2)/(3a_2) \\ a_3=(2)/(3((2)/(27))) \\ a_3=(2)/((2)/(9)) \\ a_3=(18)/(2) \\ a_3=9 \end{gathered}`
`\begin{gathered} a_4=(2)/(3a_3) \\ a_4=(2)/(3(9)) \\ a_4=(2)/(27) \end{gathered}`

Therefore for all values of n ≥ 2

`a_1=9,a_2=(2)/(27),a_3=9,a_4=(2)/(27)`