The perimeter is 32 units
1) To calculate that perimeter (2) let's calculate the distances, using a formula derived from the Pythagorean Theorem.
![d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2_{}}](https://img.qammunity.org/2023/formulas/mathematics/college/dzmv1rerjpvrh7y9ed9nd93i81hhwfhy06.png)
2) Let's calculate the distance from AB, i.e. ( -6,0) and (0,8)
![d\text{ =}\sqrt[]{(0+6)^2+(8-0)^2}=10](https://img.qammunity.org/2023/formulas/mathematics/college/1q6typr1g3ivw3mblcuxwse2b37lmv5uuv.png)
The distance, now from BC ( 0,8) to (6,0)
![d=\sqrt[]{(6-0)^2+(0-8)^2}=10](https://img.qammunity.org/2023/formulas/mathematics/college/vumjhfilh35qrp8k3szm3oa35cqrf8ab48.png)
And finally CA (6,0) to (-6,0)
![d=\sqrt[]{(-6-6)^2+(0-0)^2}=12](https://img.qammunity.org/2023/formulas/mathematics/college/mb9mqpc0qma338vw79komddo010mna38yw.png)
3) The Perimeter then, adding all the lengths will be (2P) Is: 10 +10 +12 = 32