Question

Need help on HS geometry

Answer 1

`\\ \tt\Rrightarrow 16x-27=5x+6`

`\\ \tt\Rrightarrow 16x-5x=6+27`

`\\ \tt\Rrightarrow 11x=33`

`\\ \tt\Rrightarrow x=3`

• m<YQR=16(3)-27=48-27=21°

Answer 2

• Here, RY = PY.
• Angle QRY = Angle QPY = 90°
• QY = QY [common]
• Therefore, ∆ QRY = ∆ QPY
• By c.p.c.t., angle RQY = angle PQY
• Therefore,
• 
  `16x - 27 = 5x + 6 \\ = > 16x - 5x = 6 + 27 \\ = > 11x = 33 \\ = > x = 3`
• Therefore, the measure of angle YQR
• 
  `= (16x - 27)° \\ = (16 * 3 - 27)° \\ = (48 - 27)° \\ = 21°`

Answers:

1. 3
2. 21°

Hope you could get an idea from here.

Doubt clarification - use comment section.