265,069 views
1 vote
1 vote
(I need these answered fast and with work and explanation)

A)What is the conditional probability of being on the marching band, given that you know
the student plays a team sport? Show your work.

b. What is the probability of being on the marching band, and how is this different from part
(a)? Explain completely.

C.
Are the two events, {on the marching band) and {on a team sport} associated? Use
probabilities to explain why or why not.

(I need these answered fast and with work and explanation) A)What is the conditional-example-1
User Mirco
by
2.0k points

2 Answers

25 votes
25 votes

Answer:

most I know I don't know and I don't want to know

User Flamusdiu
by
3.2k points
12 votes
12 votes

a. The conditional probability of being on the marching band, given that the student plays a team sport, is approximately 0.0171.

b. The probability of being on the marching band, regardless of team sport participation, is approximately 0.0521.

c. The events "on the marching band" and "on a team sport" are associated since they are dependent events.

How to calculate conditional probability

To answer the questions, use the given data and apply the concepts of conditional probability and independence of events.

a. To find the conditional probability of being on the marching band, given that the student plays a team sport, we need to calculate P(Marching band | Team sport). This can be done using the formula:

P(Marching band | Team sport) = P(Marching band and Team sport) / P(Team sport)

From the given data:

P(Marching band and Team sport) = 14

P(Team sport) = 818

Therefore,

P(Marching band | Team sport) = 14 / 818 ≈ 0.0171

The conditional probability of being on the marching band, given that the student plays a team sport, is approximately 0.0171.

b. The probability of being on the marching band refers to the overall probability of a student being in the marching band, regardless of whether they play a team sport or not.

This can be calculated using the formula:

P(Marching band) = (Number of students on the marching band) / (Total number of students)

From the given data:

Number of students on the marching band = 222

Total number of students = 222 + 1909 + 1313 + 818 = 4262

Therefore,

P(Marching band) = 222 / 4262 ≈ 0.0521

The probability of being on the marching band is approximately 0.0521.

The difference between part (a) and part (b) is that part (a) calculates the conditional probability of being on the marching band among students who play a team sport, while part (b) calculates the overall probability of being on the marching band, regardless of team sport participation.

c. To determine if the events "on the marching band" and "on a team sport" are associated, compare their probabilities.

If the events are independent, the probability of both events occurring should be equal to the product of their individual probabilities.

P(Marching band and Team sport) = P(Marching band) * P(Team sport)

From the given data:

P(Marching band and Team sport) = 14

P(Marching band) ≈ 0.0521

P(Team sport) = 818 / 4262 ≈ 0.1919

Calculating the product of the individual probabilities:

P(Marching band) * P(Team sport) ≈ 0.0521 * 0.1919 ≈ 0.00999

Since the product of the individual probabilities is not equal to the joint probability, the events "on the marching band" and "on a team sport" are dependent events. Therefore, they are associated.

User Sarawut Positwinyu
by
2.6k points