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Solve the equation. x/x+4 = 20/x^2+3x-4 + 2/x-1

User Bokor
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1 Answer

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Sam, this is the solution:

x/x+4 = 20/(x^2+3x-4) + 2/x-1

Step 1: Let's factor x^2+3x-4, this way:

x^2+3x-4 = (x +4) (x - 1)

Then we have:

x/x+4 = 20/(x + 4)(x -1) + 2/x-1

Step 2: Let's find the Lowest common denominator:

We have:

(x + 4), (x + 4)(x -1), (x - 1)

Lowest common denominator = (x + 4) (x - 1)

Step 3:Now we can divide (x + 4) (x - 1) by each denominator and multiply by the numerator, as follows:

x (x - 1) = 20 + 2(x + 4)

x² - x = 20 + 2x + 8

Step 4: Like terms

x² - x -2x = 28

x² - 3x - 28 = 0

Step 5: Let's factor again

(x - 7) (x + 4) = 0

Step 6: Find the solutions for x

x - 7 = 0

x1 = 7

x + 4 = 0

x = -4

x2 = -4

Sam, the equation has two solutions: (-4, 7)

User NayabSD
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