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A charge has a value of 5.5x10^-6C. Find the value of the electric field 0.02m away from it.

1 Answer

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Apply the formula:

E= kQ/d^2

Where:

E = electric field

k = constant = 9 x 10^9 Nm^2/C^2

Q= charge = 5.5x10^-6C

d= distance = 0.02m

Replacing:


E=\frac{(9*10^(^9))(5.5*10^{^(-6)})}{(0.02)^(^2)}

E = 123,750,000 N/C

User Satish Dhiman
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