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MODELING REAL LIFE After the addition of an acid, a solution has a volume of 90 milliliters. The volume of the solution is 3 milliliters greater than 3 times the volume of the solution before the acid was added. What was the original volume of the solution?

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Volume data

Solution volume= V'

Original volume = V

90 mm = Volume 1 + Volume 2

Then

( V + V') + 3 = 3V

Solve and eliminate parenthesis. Find V'

3V -V - V' = 3

2V - V' = 3

Now find V , in equation

90 - V' = V

Replace V' by 2V - 3

Then

V= 90 - V' = 90 - (2V- 3)

Now isolate V

V + 2V = 90 + 3

then

3V = 93

V= 93/3= 31

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