we have
f(x)=7x-1
g(x)=(1/7)(x+1)
Part 1
Find out (fog)(x)
(fog)(x)=f(g(x))=7(1/7)(x+1)-1=x+1-1=x
therefore
(fog)(x)=x
Part 2
Find out (gof)(x)
(gof)(x)=g(f(x))=(1/7)(7x-1+1)=x
(gof)(x)=x
Part 3
(fog)(x)=(gof)(x)=x
the answer is Yes
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