Question

Hello! I need some help with this homework question, please? The question is posted in the image below. Q9

Answer 1

The expression is given as,

`2x^2\text{ < }3x\text{ + 2 }`

Simplifying the given expression ,

`\begin{gathered} 2x^2-3x-2\text{ < 0} \\ (2x+1)(x-2)\text{ < }0 \\ (2x+1)\text{ < 0 or ( x - 2 ) < 0} \\ x\text{ > }(-1)/(2)\text{ or x < 2} \end{gathered}`

Thus the solution set is

`(-1)/(2)\text{ < x < 2}`