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An electric clock is stopped by a power failure. what is the probability of the event that he second hand is stopped between the 3 and 4?

User IanGSY
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Let's begin by listing out the given information:

An electric clock has 60 equal intervals (seconds)

Between the 3 and 4, there are 5 equal intervals (seconds)

The probability that the second hand stops between the 3 and 4 is:


\begin{gathered} P=(5)/(60)=(1)/(12) \\ P=(1)/(12) \end{gathered}

User Yali
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