Answer:

Step-by-step explanation:
The point-slope form of the equation of a line is generally given as;

where m = slope of the line
x1 and y1 = coordinates of the point.
Let's 1st of all determine the slope of the line that passes through the points with coordinates x1 = 1, x2 = -3, y1 = 3, and y2 = 0 using the below formula;

Let's go ahead and write the equation of the line in point-slope form using m = 3/4 and x1 = 1 and y1 = 3;
