Here, we want to solve the system of equation by graphing
To do this, we plot the graph of both lines on the same graph; the point at which the lines meet is the solution to the sysyem of equations
For ease of plotting, we need two points that we can join for each line
The x-intercept and the y-intercept
Generally, the equation of a straight line is;
![y\text{ = mx + c}](https://img.qammunity.org/2023/formulas/mathematics/high-school/bytb7ot4w7zxklso4u7p42dp2xh741ioqe.png)
where m is the slope and c is the y-intercept
To get the x-intercept, simpy set y to 0; to get the y -intercept, simply set x to zero
For; 7x + 3y = -12
For x-intercept;
![\begin{gathered} 7x\text{ + 3(0) = -12} \\ \\ 7x\text{ = -12} \\ \\ x\text{ = }(-12)/(7) \\ \\ For\text{ y-intercept} \\ \\ 7(0)\text{ + 3y = -12} \\ \\ 3y\text{ = -12} \\ y\text{ = }(-12)/(3) \\ \\ y\text{ = -4} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ppbxc59nhvy7sqzephxepp1lat3pgaq3gp.png)
To plot the graph of the line, simply join the points (-12/7,0) and (0,-4) with a straight line
For x - 3y = 12
![\begin{gathered} To\text{ get x-intercept} \\ \\ \text{set y = 0} \\ \\ \text{here x = 12} \\ \\ To\text{ get y-intercept, set x = 0} \\ \\ -3y\text{ = -12} \\ \\ y\text{ = }(-12)/(-3) \\ \\ y\text{ = 4} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/in5lffpd82b07up0qvy0cdifzqy0i6j220.png)
So to plot the graph of this, simply join the points (12,0) and (0,4) with a line
The point at which the line of both intersects is the solution to the system of equation