To check if a pair is a solution of an equation, we just need to replace the values for x and y-coordinates in the equation. If the equality is satisfied, then the pair is a solution to the equation.
Let's check each of the pairs given:
(2, -3) has 2 as its x-value and -3 as its y-value. Replacing those in the equation:
![\begin{gathered} 3x-2y=12 \\ 3(2)-2(-3)=12 \\ 6-(-6)=12 \\ 6+6=12 \\ 12=12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/z1rqv0d6aekpaegxhkvjiu3c74m306ceuh.png)
We can see that by solving the equation, we obtain 12 on both sides of the equation. The equality is satisfied, then the pair (2, 3) represents a solution to the equation.
Following the same process for the others:
(4, 0):
![\begin{gathered} 3\cdot4-2\cdot0=12 \\ 12-0=12 \\ 12=12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/nau9px0g53u6anfgdubwry9mdxrzydd1tv.png)
It is a solution.
(5, -1):
![\begin{gathered} 3\cdot5-2\cdot(-1)=12 \\ 15+2=12 \\ 17=12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/arxz52tbpkjphdt1vup832od2r6n0yl133.png)
Is NOT a solution.
(0, -6):
![\begin{gathered} 3\cdot0-2\cdot(-6)=12 \\ 0+12=12 \\ 12=12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/pkdmb1z7a3t901gu76f4p5cq9vra8nbrd5.png)
Is a solution.
(2, 3):
![\begin{gathered} 3\cdot2-2\cdot3=12 \\ 6-6=12 \\ 0=12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/krsnkemc8kkajd246m2xovp0mkq7grt0a3.png)
Is NOT a solution.
Now we have checked all. In summary:
(2, -3): Solution
(4, 0): Solution
(5, -1): No solution
(0, -6): Solution
(2, 3): No solution