Answer:
x-component: 10.52 m/s
y-component: 6.57 m/s
Step-by-step explanation:
The x and y-components of the velocity can be calculated using the trigonometric functions sine and cosine. So, each component is equal to
![\begin{gathered} v_x=v\cos (\theta) \\ v_y=v\sin (\theta) \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/6f2tzki8ofrh93atfl8y9qpweyy3cr2bmp.png)
Where v is 12.4 m/s and θ is the angle of 32°. So, replacing the values, we get:
![\begin{gathered} v_x=12.4\cos (32)=10.52\text{ m/s} \\ v_y=12.4\sin (32)=6.57\text{ m/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/t3u4r1y5zm9iirukwn9t609457471ds3rj.png)
Therefore, the x-component of its velocity is 10.52 m/s and the y-coordinate of its velocity is 6.57 m/s