Question

QuestionA painting frame is in the shape of an isosceles triangle with a base of 27 inches. The perimeter of the frame is 83 inches.How long is each of the equal sides of the frame?

Answer 1

Step 1:

In this question, we are given the following:

A painting frame is in the shape of an isosceles triangle with a base of 27 inches. The perimeter of the frame is 83 inches.

How long is each of the equal sides of the frame?

Step 2:

The details of the solution are as follows:

From the question, we can see that

The base of the isosceles triangle = 27 inches

Since the length of the each of the equal side = x , then we have that:

`\begin{gathered} \text{27 + x + x = 83} \\ collect\text{ like terms, we have that:} \\ \text{27 + 2x = 83} \\ \text{2x = 83 - 27} \\ \text{2x = 56} \\ Divide\text{ both sides by 2, we have that:} \\ \text{x = }(56)/(2) \\ \text{x = 28 inches} \end{gathered}`

CONCLUSION:

The final answer is:

The length of each of the equal sides of the frame = 28 inches