The pythagorean theorem is expressed as
hypotenuse^2 = one leg^2 + other leg^2
From the diagram,
hypotenuse = x
one leg = 40
other leg = 9
Thus, we have
The correct option is B
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![\begin{gathered} x^2=40^2+9^2 \\ x^2\text{ = 1600 + 81 = 1681} \\ x\text{ = }\sqrt[]{1681} \\ x\text{ = 41} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/12q1odvihuewm0vv50z76sj5wwgmia45pn.png)