Question

What is the voltage across the load, RL, in

this voltage divider network?
10.25 V
4.55 V
5.71 V
11.50 V

Answer 1

(c) 5.71 V

Step-by-step explanation:

The circuit can be redrawn to a Thevenin equivalent that is 6V through a 5-ohm resistor into a 100-ohm load. Then the voltage at the load is ...

(6 V)(100/(100 +5) ≈ 5.71 V