Question

A sample of silver at 10°C is heated to 90°C when 1 kcal of heat is added. What is the mass of the silver? (csilver = 0.056 cal/g•°C)

Answer 1

Given:

The initial temperature of the silver is

`T_i=\text{ 10}^(\circ)\text{ C}`

The final temperature of the silver is

`T_f=\text{ 90}^(\circ)\text{ C}`

The heat added is Q = 1 kcal = 1000 cal

The specific heat of silver is

`\text{C}_(silver)\text{ = 0.056 cal/g }^(\circ)C`

Required: The mass of the silver.

Step-by-step explanation:

The mass of the silver can be calculated by the formula

`\begin{gathered} Q=mC(T_f-T_i) \\ m=(Q)/(C(T_f-T_i)) \end{gathered}`

On substituting the values, the mass will be

`\begin{gathered} m=(1000)/(0.056*(90-10)) \\ =223.21\text{ g} \end{gathered}`

Final Answer: The mass of the silver is 223.31 g