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A star has a surface area of 6.29x1018 m2. How much power does it radiate if it has a surface temperature of 7005 K? Submit your answer in exponential form.

User Nyxynyxx
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we are asked to determine the power irradiated by a star given its area and temperature.

To do that we will use the following formula:


P=\sigma AT^4

Where:


\begin{gathered} P=power \\ A=\text{ area} \\ T=\text{ temperature} \\ \sigma=\text{ constant} \end{gathered}

The constant sigma is equivalent to:


\sigma=5.7*10^(-8)Wm^(-2)K^(-4)

Now, we substitute the values:


P=(5.7*10^(-8)Wm^(-2)K^(-4))(6.29*10^(18)m^2)(7005K)^4

Solving the operations:


P=8.63*10^(16)W

And thus we get the power of the start.

User Warren Weckesser
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