Question

For triangle MNO let angle M = 90°, if the measure of MO = 22 and the measure of NO = 58.6, what is the measure of angle O

Answer 1

Required; To find angle O

Using trigonometric ratio

`\cos o\text{ =}\frac{adjacent\text{ }}{\text{hypothenus}}`

Adjacent = 22

hypothenus = 58.6

`\begin{gathered} \text{Cos }O\text{ =}(22)/(58.6) \\ O\text{ =}\cos ^(-1)(0.3754) \\ O=67.95^(\circ) \\ O\approx68^(\circ) \\ \end{gathered}`