Question

In triangle CDE,m angle C=52,m angle D=17 , and e = 29.6 . Find c to the nearest tenth

Answer 1

The triangle can be drawn as,

The value of angle E can be determined as,

`\begin{gathered} 17+52+\angle E=180 \\ \angle E=111^(\circ) \end{gathered}`

The value of c can be determined from the sine rule as,

`\begin{gathered} (e)/(\sin E)=(c)/(sinC) \\ (29.6)/(\sin 111^(\circ))=(c)/(\sin 52^(\circ)) \\ c=24.98 \\ \approx25.0 \end{gathered}`

Thus, the value of c to the nearest tenth is 25.0.