Question

Drag each label and/or number to the correct location on the table. Not all labels and/or numbers will be used.40 units DESegmentALengthED-4 -2FIy4√10 units0+642++2++4+-68IC34 units AC AB2Use the graph to complete the table for missing segment names and segment lengths.BCB6G8+x346 units√181 unitsEFFG√125 units

Answer 1

Given the points plotted on the Coordinate Plane:

• You can find the length of the segment BC by finding the distance between the points B and C.

You need to use the formula for calculating the distance between two points:

`d=√((x_2-x_1)^2+(y_2-y_1)^2)`

Where the following are the two points:

`\begin{gathered} (x_1,y_1) \\ (x_2,y_2) \end{gathered}`

In this case, you can identify that:

`\begin{gathered} B(3,-4) \\ C(1,2) \end{gathered}`

Then, by substituting the corresponding coordinates into the formula and evaluating, you get:

`BC=√((1-3)^2+(2-(-4))^2)=√(40)\text{ }units`

• You can find the length of the segment FG by finding the distance between the points F and G.

Notice that:

`\begin{gathered} F(-3,-6) \\ G(8,9) \end{gathered}`

Using the same formula, you get:

`FG=√((8-(-3))^2+(9-(-6))^2)=√(346)\text{ }units`

• Notice that:

`\begin{gathered} A(-7,5) \\ C(1,2) \end{gathered}`

Using the same formula, you can find the length of the segment AC:

`AC=√((1-(-7))^2+(2-5)^2)=√(73)\text{ }units`

• You can identify that:

`\begin{gathered} D(-5,-8) \\ E(-8,-9) \end{gathered}`

Then, the length of the segment DE is:

`DE=√((-8-(-5))^2+(-9-(-8))^2)=√(10)\text{ }units`

• Notice that:

`B(3,-4)`

Then, the length of the segment AB is:

`AB=√((3-(-7))^2+(-4-5)^2)=√(181)\text{ }units`

• You can find the length of the segment EF:

`EF=√((-3-(-8))^2+(-9-(-6))^2)=√(34)\text{ }units`

Hence, the answer is: