we can find the cost per ounce using cross multiplication
1.jar

where x is the cost per ounce

The cost per ounce is $0.08
2.Jar

where y is the cost per ounce

The cost per ounce is $0.09
3.Jar

where z is the cost per ounce

The cost per ounce is $0.11
the best buy is the first jar because it's cheaper per ounce