Given
students enroll = 69%
n = 178
Find
probability that at most 67 % enrolled in college directiy after high school graduation
Step-by-step explanation
Let p be the proportion of students in the united states enroll directly after high school graduation.
p = 69% = 0.69
q = 1 - p = 1 - 0.69 = 0.31
n = 178
we have to find

Final Answer
probability that at most 67 % enrolled in college directiy after high school graduation = 0.280