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Graph the line y= −5/2x + 2, then name the slope and y-intercept by looking at the graph.

Graph the line y= −5/2x + 2, then name the slope and y-intercept by looking at the-example-1

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ANSWER and EXPLANATION

We want to graph the given function:


y=-(5)/(2)x+2

To do that, we have to find two points that lie on the line.

Let us solve for y when x is 0 and 2.

When x = 0:


\begin{gathered} y=-(5)/(2)(0)+2 \\ y=0+2 \\ y=2 \end{gathered}

When x = 2:


\begin{gathered} y=-(5)/(2)(2)+2 \\ y=-5+2 \\ y=-3 \end{gathered}

Now, we have two points to plot the line: (0, 2) and (2, -3)

Let us plot the graph:

From the graph, we see that the slope of the graph is:


m=-(5)/(2)

and the y-intercept is:


b=2

Graph the line y= −5/2x + 2, then name the slope and y-intercept by looking at the-example-1
User Jack Maessen
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