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find the lateral area of a right pentagonal pyramid where each side of it's base is 4 inches and its slant height is 12 inches

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Total surface of a pentagonal pyramid = (5/2)ab + (5/2)bs

Base surface = (5/2)ab

Sides surface = (5/2)bs

Where b is the size of the side, s is the slant height and a is the distance from the center the pentagonal base to the center of one of its sides

Since we have the slant height and the size of each sides, but we don't have "a", we have to calcualte it

The distance "a" can be calculated by:

tan 36° = (b/2)/a ==> a = (b/2)/tan 36° = (4/2)/0.726542528 = 2/0.726542528 = 2.752763841

a = 2.752763841

Now we can calcualte the surface:

Surface = (5/2)ab + (5/2)bs = (5/2) * 2.75 * 4 + (5/2) * 4 * 12 = 27.5 + 120 = 147.5 square inches

Answer:

Total surface = 147.5

Base surface = 27.5

Sides surface = 120

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