![x=-(9)/(5),y=-(8)/(5)](https://img.qammunity.org/2023/formulas/mathematics/college/mcu8y67zhafsr7lrshl5jjs3c1cjmv4ux9.png)
1) As the chosen method to solve this Linear System of equations then we can write out the following:
![\mleft\{\begin{matrix}y=2x+2 \\ y=7x+11\end{matrix}\mright.](https://img.qammunity.org/2023/formulas/mathematics/college/lxx65ayu5nn0kt84sd0ds5ecjmk8hv64wa.png)
2)Let's start with the simplest equation between them. And then, plug into that the value of "y". This way:
![\begin{gathered} \mleft\{\begin{matrix}I)y=2x+2 \\ II)y=7x+11\end{matrix}\mright. \\ I)y=2x+2 \\ 7x+11=2x+2 \\ 7x+11-2x=2x-2x+2 \\ 5x+11=2 \\ 5x+11-11=2-11 \\ 5x=-9 \\ (5x)/(5)=-(9)/(5) \\ x=-(9)/(5) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/m8gdm1yr13lrklz1xxee8wodfadsdtscuu.png)
Now, that we know the quantity of "x", let's plug it into any one of those equations.
3)Let's pick the 2nd one and solve it for "y".
![\begin{gathered} y=7x+11,x=-(9)/(5) \\ y=7(-(9)/(5))+11 \\ y=-(63)/(5)+11 \\ y=-(63)/(5)+(55)/(5) \\ y=-(8)/(5) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/obgehw27i4np7vuzw68vz3pj0vkgn53ld1.png)
Thus, the answer is:
![x=-(9)/(5),y=-(8)/(5)](https://img.qammunity.org/2023/formulas/mathematics/college/mcu8y67zhafsr7lrshl5jjs3c1cjmv4ux9.png)