Question

`x = (y + 8)^(3) + 7`solve equation for y(for cube root, use a power of 1/3)rewrite equation in y= form

Answer 1

Solve the equation for y by isolating that term in one side of the equation, this way:

`\begin{gathered} x=(y+8)^{(1)/(3)}+7 \\ x-7=(y+8)^{(1)/(3)} \\ (x-7)^3=y+8 \\ (x-7)^3-8=y \\ y=(x-7)^3-8 \end{gathered}`