Question

SOLUTION: a solution containing 28% fungicide is to be mixed with a solution containing 40% fungicide to make 300L of a solution containing 36% fungicide. how much of each solution should be used?

Answer 1

100L of 28% fungicide and 200L of 40% fungicide

Step-by-step explanation:

let the amount of fungicide for 28% = x

let the amount for the 40% fungicide = y

percentage for the solution = 36%

Amount in the final solution = 300L

amount for the 28% fungicide + amount for the 40% fungicide = Amount in the final solution

x + y = 300 ...equation 1

28%(amount for the 28% fungicide ) + 40%(amount for the 40% fungicide) = 36%(Amount in the final solution)

0.28(x) + 0.4(y) = 0.36(300)

0.28x + 0.4y = 108 ...equation 2

using substitution method:

make x the subject of formula from equation 1:

x = 300 - y

substitute for x in equation 2:

0.28(300 - y) + 0.4y = 108

84 - 0.28y + 0.4y = 108

0.12y = 108 - 84

0.12y = 24

y =24/0.12

y = 200

Substitute for y in equation 1:

x + 200 = 300

x = 300 - 200

x = 100

So we need 100L of 28% fungicide and 200L of 40% fungicide