Step-by-step explanation
(a) The balanced equation of the reaction is:
![2Al_((s))+6HCl_((g))\rightarrow2AlCl_(3(s))+3H_2](https://img.qammunity.org/2023/formulas/chemistry/college/8irofvfjm30654lvkiohmk38v29g8h0k90.png)
The compound F is solid AlCl₃
(b) When the solid AlCl₃ is heated to 900 °C, it changes from a solid to a gaseous state. The illustration of the change is shown below:
![\text{AlCl}_(3(s))+heat(900^oC)\rightarrow AlCl_((g))](https://img.qammunity.org/2023/formulas/chemistry/college/v00nh3qcjrhwg71adips3rh0ifo2op136q.png)
(c) Melting point of AlF₃ is high as compared to AlCl₃ because AlF₃ is an ionic compound while AlCl₃ is a covalent compound but the bond in AlCl₃ is a polar covalent bond. Melting points of ionic compounds are usually high as compared to covalent bonds because an ionic bond is stronger as compared to covalent bonds. Also, AlCl₃ has a simple molecular structure with weak van der Waals forces between its molecules. More energy is needed to overcome the strong ionic bonds in AlF₃ than the weak intermolecular forces in AlCl₃, hence AlF₃ has a much higher melting point.