
1) The first thing to consider when we tackle this question, is to make use of a z-score to construct that required interval of confidence: 90%
2) Let's gather from the data and write out the following:

Note that we resorted to a table to find the z score.
2.2. The next step is to figure out the Lower and the Upper Limits :
![\begin{gathered} Lower\: Limit\colon \\ \pi-z\sqrt[]{(\pi(1-\pi))/(n)}=(350)/(700)-1.645\sqrt[]{(0.5(1-0.5))/(700)}=.4689 \\ Upper\: Limit\colon \\ \pi+z\sqrt[]{(\pi(1-\pi))/(n)}=(350)/(700)+1.645\sqrt[]{(0.5(1-0.5))/(700)}=.5311 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/z2jsvlnurnbovuny31k2y5lsdsec4mhdkv.png)
Once we have the lower and the upper limit, we can state that the answer is:
