For this problem, we are given a certain exponential equation. We need to solve it for "r".
The equation is:
![20^r=56](https://img.qammunity.org/2023/formulas/mathematics/college/6w1hh5f4clfheqszt1jenuzmpmn2u31v5d.png)
The first step is to apply a logarithm on both sides:
![\begin{gathered} \log20^r=\log56 \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/o56pq1kgr4nu0zh7i5ursg0sfzhdn2ffp4.png)
Now we can use the exponent rule to isolate the "r"
![\begin{gathered} r\log20=\log56\\ \\ r=(\log56)/(\log20)=1.34369 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/mptt886oadhge0qu1d0shq9t2hcb0c69q0.png)
The real solution for this problem is 1.34.